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x^2+2x^2=45^2
We move all terms to the left:
x^2+2x^2-(45^2)=0
We add all the numbers together, and all the variables
3x^2-2025=0
a = 3; b = 0; c = -2025;
Δ = b2-4ac
Δ = 02-4·3·(-2025)
Δ = 24300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24300}=\sqrt{8100*3}=\sqrt{8100}*\sqrt{3}=90\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90\sqrt{3}}{2*3}=\frac{0-90\sqrt{3}}{6} =-\frac{90\sqrt{3}}{6} =-15\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90\sqrt{3}}{2*3}=\frac{0+90\sqrt{3}}{6} =\frac{90\sqrt{3}}{6} =15\sqrt{3} $
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